a)
4
Σ 1
i=1
b) 4
Σ i^2
i=1
hence evaluate
4
Σ [(i+1)(i-1)]
i=1
can anyone explain this briefly to me please.. thx a lot
更新1:
why (a) is 1+1+1+1 ?? THANKS
sigma equation S4 M2
2011-10-31 5:36 am
Evaluate the following sums
a)
4
Σ 1
i=1
b) 4
Σ i^2
i=1
hence evaluate
4
Σ [(i+1)(i-1)]
i=1
can anyone explain this briefly to me please.. thx a lot
a)
4
Σ 1
i=1
b) 4
Σ i^2
i=1
hence evaluate
4
Σ [(i+1)(i-1)]
i=1
can anyone explain this briefly to me please.. thx a lot
回答 (2)
2011-10-31 5:41 am
✔ 最佳答案
(a) The value is equal to 1 + 1 + 1 + 1 = 4(b) The value is equal to 1^2 + 2^2 + 3^2 + 4^2 = 30
(c) The value is equal to 2 * 0 + 3 * 1 + 4 * 2 + 5 * 3 = 26
2011-11-01 2:14 am
Q:why (a) is 1+1+1+1 ??
A:
Since the i is with respective to the i in the term 1,
as 1 does not have i,
we concludes that each term in the summation will not be affected.
Therefore, it equals 1+1+1+1 = 4
A:
Since the i is with respective to the i in the term 1,
as 1 does not have i,
we concludes that each term in the summation will not be affected.
Therefore, it equals 1+1+1+1 = 4
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