要列式
1) 5(z+1)-8(z-3) = 11
2) 3b+12÷9 = 6b-2÷5
3) -(7p-3)÷5-3p = 27
4) 22-3r÷2 = r÷5-6
中一一元一次方程(15點)
2011-10-31 4:56 am
回答 (2)
2011-10-31 6:13 am
✔ 最佳答案
1) 5(z+1)-8(z-3) = 115z+5-8z+24 = 11
29-3z = 11
z = 6
2) 3b+12÷9 = 6b-2÷5
12/9+2/5 = 6b-3b
26/15 = 3b
b = 26/45
3) -(7p-3)÷5-3p = 27
-(7p-3)/5 = 27+3p
-7p+3 = 135+15p
-22p = 132
p = -6
4) 22-3r÷2 = r÷5-6
22+6 = r/5+3r/2
28 = 17r/10
r = 280/17
參考: myself
2011-10-31 6:37 am
1) 5(z+1)-8(-3)=11
5z+5-8z-24 =11
-3z-19=11
-3z-19+19=11+19
-3z=30
-z =10
z=-10
5z+5-8z-24 =11
-3z-19=11
-3z-19+19=11+19
-3z=30
-z =10
z=-10
收錄日期: 2021-04-16 13:38:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20111030000051KK01034