i found out that dy/dx of e^4x + e^-x? is e^-x(4e^(5x) -1)
but what is d^2y/dx^2?
d^2y/dx^2 of e^4x + e^-x?
2011-10-26 1:04 pm
回答 (2)
2011-10-26 2:27 pm
✔ 最佳答案
y = e^uy' = u'e^u
dy/dx = 4e^4x - e^-x
d^2y/dx^2 = (4)(4)e^4x + e^-x
參考: And I made a mistake in your last question.
http://answers.yahoo.com/question/index;_ylt=AgZyoIeqVZqcTA.L_3FU25_ty6IX;_ylv=3?qid=20111025051803AA9PemW
2011-10-26 1:07 pm
You have done the dy/dx incorrectly:
This should be 4e^4x - e^-x
Then d^2y/dx^2 is 16e^4x + e^-x
This should be 4e^4x - e^-x
Then d^2y/dx^2 is 16e^4x + e^-x
收錄日期: 2021-05-01 00:52:41
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20111026050437AAWKNTg