what is the integration for xcos2x dx?
and steps please.
(urgent)what is the integration for xcos2x dx?
2011-10-25 1:18 pm
回答 (3)
2011-10-25 1:27 pm
✔ 最佳答案
integration for xcos2x dx = (1/2)(sin 2x) + c
2011-10-25 8:31 pm
⫠xcos2x dx=½⫠x d(sin2x)= ½x*sin2x - ½⫠sin2x dx=
= ½x*sin2x + ¼cos2x+C
http://www.wolframalpha.com/input/?i=%E2%88%AB+xcos%282x%29+dx
= ½x*sin2x + ¼cos2x+C
http://www.wolframalpha.com/input/?i=%E2%88%AB+xcos%282x%29+dx
參考: .
2011-10-25 8:26 pm
The rule is: integration of cos(ax + b) = (1/a)[sin(ax + b)] +c
for you, a = 2 and b = 0 so...
the integral of xcos2x dx = (1/2)[sin2x] + c
for you, a = 2 and b = 0 so...
the integral of xcos2x dx = (1/2)[sin2x] + c
收錄日期: 2021-05-01 00:56:55
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