✔ 最佳答案
3α and 3β are the roots of x^2 + px + q = 0
3(α+β) = -p and 9αβ = q
So,
(α + 2β) + (β + 2α) = 3(α+β) = -p
(α + 2β)(β + 2α)
= 2(α^2 + β^2) + 5αβ
= 2(α+β)^2 + αβ
= 2p^2/9 + q/9
So, the quadratic equation in x whose roots are α+2β and β+2α is
x^2 + px + 2p^2/9 + q/9 = 0 or
9x^2 + 9px + (2p^2 + q) = 0