Q:Integrate ∫dx/√(2-5x)
A:
Put √(2-5x)=u
2-5x=u²
5x=2-u²
x=(1/5)(2-u²)
dx/du=(1/5)(-2u)
dx=(-2u/5)du
So,
∫dx/√(2-5x)
=∫(-2u/5)du/u
=∫(-2/5)du
=0
WHAT'S WRONG??
1 integration Q(What's Wrong?)
2011-10-20 12:19 am
回答 (1)
2011-10-20 12:33 am
✔ 最佳答案
∫(-2/5) du is not zero, instead:∫(-2/5) du = -2u/5 + C since -2/5 is a constant
= -(2/5) √(2 - 5x) + C
參考: 原創答案
收錄日期: 2021-04-13 18:19:31
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20111019000051KK00460