electricity and magnetism

2011-10-15 6:35 am

回答 (1)

2011-10-15 7:14 am
✔ 最佳答案
(a) Horizontal component of the earth field = (5.2 x 10^-5).cos(20) T
= 4.886 x 10^-5 T

Hence, force acting on the conductor
= (4.886x10^-5) x 2 x 50 N = 4.886 x 10^-3 N

(b) Vertical component of earth field
= (5.2x10^-5).sin(20) T = 1.779 x 10^-5 T

Hence, force acting on the conductor
= (1.779 x 10^-5) x 2 x 50 N = 1.779 x 10^-3 N

(c) Force acting on the conductor
= (5.2 x 10^-5) x 2 x 50 N = 5.2 x 10^-3 N


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