電路問題一則 關於電壓

2011-10-15 3:06 am
點解電路中,由電池得到既電動勢,例如20V

假設完整電路中只有一個燈泡

點解20V的電動勢一定會完全提供給燈泡
即燈炮之間的電勢差一定為20V?燈泡未端的每C電荷能量一定為0V?

難道即使1V也沒有嗎?

或者是故意的,電路設計一定要使燈泡完整吸收20V的電壓,是嗎?
更新1:

Could you cut it short? 唔太明,可能未係知識範圍

回答 (3)

2011-10-20 7:22 am
✔ 最佳答案
你的想法是對的, 任何的電路有負載就有電壓降, 就算是0.0001V也是電壓降, 所以電路設計一定要計算電壓降的, 還有就是電源的内阻(就算是乾電池也有内阻), 也會有導致電壓降的機會, 你的結論就是燈泡完整吸收20V的電壓是不對的, 可能是19.9999V
2011-10-15 8:36 am
Just think of a battery as a source supplying charges. The +ve pole of a battery has an accumulation of +ve charges, thus possesses a +ve potential. The -ve pole of the battery has an accumulation of -ve charges, thus has a -ve potential. The +ve potential at the +ve pole and the -ve potential at the -ve pole then constitute the emf (electromotive force) of the battery.

When a light bulb is now connected to the battery, one end to the +ve pole and the other end to the -ve pole. The bulb then acquires +ve charge from the +ve pole and -ve charge from the -ve pole. Because these are the same charges as those originally in the battery, the potential difference (or voltage) across the bulb should also be the same as that of the battetry. Hence, a 10-volt battery will supply 10 volts across a bulb that is connected to it.




2011-10-15 6:04 am


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