某學生利用電熱器加熱一個缸內的液體.電熱器在30分鐘內輸出了2.7MJ的能量.
a)求電熱器的平圴功率.
B)假設只有80%的輸出能量轉移液體.,求轉移1MJ的液體.所要的時間.
請問可否解說,謝
物理中三計算
2011-10-14 1:06 am
回答 (2)
2011-10-14 3:50 am
✔ 最佳答案
(a) Power = 2.7x10^6/(30x60) J/s = 1500 J/s = 1500 watts(b) Amount of energy produced by the heater for 1 MJ of energy transferred
= 1 x 10^6 x (100/80) J = 1.25 x 10^6 J
Time neede for the transfer
= 1.25x10^6/1500 s = 833 s =13.88 minutes
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