factorize 3(x+7)^2+(x+7)(x-6)-14(x-6)^2
吾該曬...
f3 factorization!!!help!!!
2011-10-10 2:48 am
回答 (3)
2011-10-10 2:58 am
✔ 最佳答案
Let x+7=y, x-6=z3(x+7)^2+(x+7)(x-6)-14(x-6)^2
=3y^2+yz-14z^2
=(3y+7z)(y-2z)
=(3x+21+7x-42)(x+7-2x+12)
=(10x-21)(19-x)
參考: my brain
2011-10-19 3:01 am
Let x+7=y, x-6=z
3(x+7)^2+(x+7)(x-6)-14(x-6)^2
=3y^2+yz-14z^2
=(3y+7z)(y-2z)
=(3x+21+7x-42)(x+7-2x+12)
=(10x-21)(19-x)
^_^
3(x+7)^2+(x+7)(x-6)-14(x-6)^2
=3y^2+yz-14z^2
=(3y+7z)(y-2z)
=(3x+21+7x-42)(x+7-2x+12)
=(10x-21)(19-x)
^_^
2011-10-16 2:48 am
設a=(x+7) b=(x-6)
3(x+7)^2+(x+7)(x-6)-14(x-6)^2
=3a^2+ab-14b^2
=(3a+7b)(a-2b)
=[3(x+7)+7(x-6)][(x+7)-2(x-6)]
=(3x+21+7x-42)(x+7-2x+12)
=(10x-21)(-x+19)
3(x+7)^2+(x+7)(x-6)-14(x-6)^2
=3a^2+ab-14b^2
=(3a+7b)(a-2b)
=[3(x+7)+7(x-6)][(x+7)-2(x-6)]
=(3x+21+7x-42)(x+7-2x+12)
=(10x-21)(-x+19)
收錄日期: 2021-04-23 22:26:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20111009000051KK00888