✔ 最佳答案
log(x + 3) + log(x - 3) = 3log3
log[(x + 3)(x - 3)] = log9 ...... (loga + logb= logab)
log[(x + 3)(x - 3)] = log3³ ...... (logaᵏ =kloga)
(x + 3)(x - 3) = 3³ ...... (If loga = logb, thena = b)
x² - 9 = 27 ......(Expansion of (x + 3)(x - 3))
x² = 36...... (rearrangement)
x = 6or x = -6(rejected for log of negative number is undefined)
Hence, x= 6