✔ 最佳答案
1. Apply Ohm's Law to the whole circuit
8 + 6 - 6 = I.(3+9+4)
hence, I = 8/16 A = 0.5 A
Therefore, the reading on the ammeter is 0.5 A
Voltage across voltmeter = p.d across 4-ohm resistor + p.d. across 3-ohm resistor - emf of 6v cell
i.e. voltmeter reading = (-4 x0.5 - 3 x 0.5 + 6) v = 2.5 v
2. Consider the whole loop, apply Ohm's Law,
12 - 9 = 7(I1) + 8(I2) -------------------------- (1)
Consoder the left loop,
12 = 7(I1) - 4(I3) ------------------------ (2)
At the junction between the 7-ohm and 8-ohm resistors,
I2 = I1 + I3 -------------------- (3)
Solve these 3 equations for the values of I1, I2 and I3, we have,
I1 = 0.931 A
I2 = -0.44 A
I3 = -1.371 A
The -ve signs of I2 and I3 indicate the currents I2 and I3 are, in fact, flowing in the reverse direction to those shown on the figure.