請幫忙計算以下題:
第一題: (-5 1/3)(1/9)-(1 5/6)(-2 3/4)
(負五又三分一)(九分一) 減 (一又六分五)(負二又四分三)
請問點計?
第二題: -2/3(-4)2-62(-3/7)
中一正負數
2011-10-08 7:44 am
回答 (4)
2011-10-08 3:59 pm
✔ 最佳答案
(-5 - 1/3)(1/9) - (1 + 5/6)(-2 - 3/4)= (-16/3)(1/9) - (11/6)(-11/4)
= -16/27 + 121/24
= -16*8/216 + 121*9/216
= (121*9 - 16*8)/216
= 961/216
= 4 + 97/216
= 4 又97/216
(-2/3)(-4)^2 - 6^2 (-3/7)
= (-2/3)(16) - 36(-3/7)
= - 32/3 + 108/7
= -32*7/21 + 108*3/21
= (108*3 - 32*7)/21
= 100/21
= 4+16/21
= 4又16/ 21
2011-10-09 2:12 am
1.
(-5 - 1/3)(1/9) - (1 + 5/6)(-2 - 3/4)
= (-16/3)(1/9) - (11/6)(-11/4)
= -16/27 + 121/24
= -16*8/216 + 121*9/216
= (121*9 - 16*8)/216
= 961/216
= 4 + 97/216
= 4又216分97
2.
(-2/3)(-4)^2 - 6^2 (-3/7)
= (-2/3)(16) - 36(-3/7)
= - 32/3 + 108/7
= -32*7/21 + 108*3/21
= (108*3 - 32*7)/21
= 100/21
= 4+16/21
= 4又21分16
(-5 - 1/3)(1/9) - (1 + 5/6)(-2 - 3/4)
= (-16/3)(1/9) - (11/6)(-11/4)
= -16/27 + 121/24
= -16*8/216 + 121*9/216
= (121*9 - 16*8)/216
= 961/216
= 4 + 97/216
= 4又216分97
2.
(-2/3)(-4)^2 - 6^2 (-3/7)
= (-2/3)(16) - 36(-3/7)
= - 32/3 + 108/7
= -32*7/21 + 108*3/21
= (108*3 - 32*7)/21
= 100/21
= 4+16/21
= 4又21分16
2011-10-08 11:49 pm
1.
(-5又3分1)(9分1)-(1又6分5)(-2又4分3)
=(-16/3)(1/9)-(11/6)(-1/4)
=-16/27+121/24
=961/216
2.
-2/3(-4)^2-6^2 (-3/7)
=16(-2/3)-36(-3/7)
=-32/3+108/7
=100/21
(-5又3分1)(9分1)-(1又6分5)(-2又4分3)
=(-16/3)(1/9)-(11/6)(-1/4)
=-16/27+121/24
=961/216
2.
-2/3(-4)^2-6^2 (-3/7)
=16(-2/3)-36(-3/7)
=-32/3+108/7
=100/21
2011-10-08 8:05 am
收錄日期: 2021-04-16 13:35:47
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20111007000051KK00899