lim(n→∞)
(2^n){∛[(-1+√3i)/(2^(3n+1))]+∛[(-1-√3i)/(2^(3n+1))]}
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1 difficult limit Q
2011-10-08 5:44 am
回答 (2)
2011-10-08 10:08 pm
2011-10-08 6:20 am
lim(n→∞) ∛[(-1+√3i)/(2^(3n+1))] = 0
lim(n→∞) ∛[(-1-√3i)/(2^(3n+1))] = 0
therefore
lim(n→∞)
(2^n){∛[(-1+√3i)/(2^(3n+1))]+∛[(-1-√3i)/(2^(3n+1))]}
=0
lim(n→∞) ∛[(-1-√3i)/(2^(3n+1))] = 0
therefore
lim(n→∞)
(2^n){∛[(-1+√3i)/(2^(3n+1))]+∛[(-1-√3i)/(2^(3n+1))]}
=0
收錄日期: 2021-04-13 18:17:01
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20111007000051KK00766