Do You Know 1=2 ?
2011-10-06 1:40 am
Let a=b
a²=ab
ab=a²
ab-2ab=a²-2ab
ab-2ab+a²=a²-2ab+a²
a²-ab=2a²-2ab
a²-ab=2(a²-ab)
(a²-ab)/(a²-ab)=[2(a²-ab)]/(a²-ab)
1=2
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回答 (3)
2011-10-11 2:42 pm
唔！"............
2011-10-06 4:07 am
(a+b)(a-b)=2(a+b)(a-b)
(a-b)=0
??!!
(a-b)=0
??!!
2011-10-06 4:01 am
Let a=b
a²=ab
ab=a²
ab-2ab=a²-2ab
ab-2ab+a²=a²-2ab+a²
a²-ab=2a²-2ab
-----------
a²-ab=2a²-2ab
a²-b²= 2(a²-b²)
(a+b)(a-b)=2(a+b)(a-b)
(a-b)=0
0=0
2011-10-10 23:49:54 補充：
因為 a=b
所以 a-b =0
但文章中卻在等式兩邊約了(a-b)
0唔係可除數
所以係計錯
a²=ab
ab=a²
ab-2ab=a²-2ab
ab-2ab+a²=a²-2ab+a²
a²-ab=2a²-2ab
-----------
a²-ab=2a²-2ab
a²-b²= 2(a²-b²)
(a+b)(a-b)=2(a+b)(a-b)
(a-b)=0
0=0
2011-10-10 23:49:54 補充：
因為 a=b
所以 a-b =0
但文章中卻在等式兩邊約了(a-b)
0唔係可除數
所以係計錯
收錄日期: 2021-04-13 18:17:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20111005000050KK00788