四元不等式

2011-10-01 8:22 pm

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回答 (1)

2011-10-01 9:33 pm
✔ 最佳答案
Let a = 1/(1+w) , b = 1/(1+x) , c = 1/(1+y) , d = 1/(1+z) , then a + b + c + d ≤ 1.
w x y z
= (1 - a)/a * (1 - b)/b * (1 - c)/c * (1 - d)/d
≥ (a+b+c+d - a)/a * (a+b+c+d - b)/b * (a+b+c+d - c)/c * (a+b+c+d - d)/d
= (b+c+d)/a * (a+c+d)/b * (a+b+d)/c * (a+b+c)/d
≥ 3∛(bcd) / a * 3∛(acd) / b * 3∛(abd) / c * 3∛(abc) / d
= 81


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