簡單數學(送分) (10)

2011-09-29 12:00 am
4[(6-x)/6] 點計, 要步驟。thx!!

回答 (5)

2011-10-03 12:23 am
✔ 最佳答案
您好,我是 lop,高興能解答您的問題。

4[(6-x)/6]
= 4(6-x)/6
= [4(6-x)]/6
= [4(6)-4x]/6
= (24-4x)/6
= [2(12)-2(2x)]/6
= 2(12-2x)/2(3)註(1)
= (12-2x)/3
= 12/3 - 2x/3
= 4 - 2x/3

註:

(1) 約分,分子分母約掉 2
參考: Hope I Can Help You ^_^ ( From me )
2011-10-02 3:35 am
001,
4[(6 - x)/6]
= 4(6/6 - x/6)
= 4[1- (x)/6]
= 4 - (4x)/6
= (12 - 8x)/12

應該係錯的,係呢一行:
= 4 - (4x)/6
再計落去,應該係
(24/6)-(4x6)
=4(6-x)/6
=2(6-x)/3
=(12-2x)/3
2011-10-02 12:17 am
4[(6-x)/6]
=(2*2)[(6-x)/(2*3)]
=2[(6-x)/3]
=2(6-x)/3
=(12-2x)/3
參考: Hope I Can Help You! ^_^ ( From Me )
2011-09-29 2:56 am
4[(6 - x)/6]
= 4[6/6 - x/6]
= 4[1 - x/6]
= 4*1 - 4*x/6
= 4 - 4x/6
= 4 - 2x/3
2011-09-29 2:03 am
4[(6 - x)/6]
= 4(6/6 - x/6)
= 4[1- (x)/6]
= 4 - (4x)/6
= (12 - 8x)/12

Hope I can help you.


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