Maths等比數列一問

2011-09-28 10:27 pm
這題想了很久也想不到,書中也沒例題所以來發問,希望有人可幫忙~

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回答 (1)

2011-09-28 11:31 pm
✔ 最佳答案
a)

設T(n)=aR^(n-1) a是首項,R是公比



a+aR=4 -----(1)
a+aR+aR^2 = 14/3 -----(2)
a+aR+aR^2+aR^3 = 40/9 -----(3)

put (2) into (3), we have

aR^3 = 40/9 - 14/3 =-2/9 ----- (4)

put (1) into (2), we have

aR^2 = 14/3 -4 =2/3 ----(5)

(4)/(5), we have

R = (-2/9) / (2/3)
=-1/3

put it into (5), we have

a(-1/3)^2 = 2/3

a=6

b) Sum = a/(1-R) = 6/(1+1/3) = 9/2

希望幫到你!


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