✔ 最佳答案
37.
(a)
T(n): The distance in m that the snake moves in the nth second.
T(1) = 2
T(2) = 2 ´ (2/3)
T(3) = 2 ´ (2/3)^2
......
T(n) = 2 ´ (2/3)^(n - 1)
T(1), T(2), T(3), ...... ,T(n), ..... form a geometric sequence, where
the first term, T(1) = a = 2
and the common ratio, r = 2/3
S(5)
= a(1 - r^n)/(1 - r)
= 2[1 - (2/3)^5] / [1 - (2/3)]
= 2[1 - (32/243)] / (1/3)
= (422/243) / (1/3)
= 422/81
The total distance that the snake has moved in the 1st 5 seconds
= 422/81 m
≈ 5.21 m
(b)
S(∞)
= a/(1 - r)
= 2/[1 - (2/3)]
= 6
The total distance that the snake can travel
= 6 m