find the constant term in the expansion of (1+2/x)^3 (3+x)^6.
how to do
maths m1
2011-09-25 2:16 am
回答 (1)
2011-09-25 4:08 am
✔ 最佳答案
Constant term= 1*3 + (3C1*2)(6C1*3^5)+(3C2*2^2)(6C2*3^4)+(2^3)(6C3*3^3)
= 3 + 8748 + 14580+4320
= 27651
參考: Hope the solution can help you^^”
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