✔ 最佳答案
P(The system will function normally)
= P(Machine a function normally) * P(At least two of the machines b,c,d and e work)
= P(Machine a function normally) * P(Any two of b , c , d , e work)
+ P(Machine a function normally) * P(Any three of b , c , d , e work)
+ P(Machine a function normally) * P(All of b , c , d , e work)
= 0.7 * (4C2) * 0.6² * 0.4²
+ 0.7 * (4C3) * 0.6³ * 0.4
+ 0.7 * (4C4) * 0.6⁴
= 0.24192
+ 0.24192
+ 0.09072
= 0.57456