(Poisson distribution)question on Discrete Random Variables?

2011-09-22 10:23 am
On average a typist has to correct one word in every 800 words. Each page contains 200 words.
If more than one correction per page is required, the page needs to be retyped. What is the probability that more then two attempts are needed before a page is deemed satisfactory?

working steps please thank you!

just for double check:
ans is 0.0007

回答 (2)

2011-09-22 10:35 am
✔ 最佳答案
mean m per page = 0.25
P[x] = e^-m *m^x/x!
P[>1] = 1 - {P[0] - P[1]} = 1 - e^-0.25 (1+0.25) = 0.0265 = P[page needs retyping]
if 2 successive pages are bad, more than 2 attempts will be needed
P[2 ] = 0.0265^2 = 0.0007

QED
2016-12-02 9:57 am
A discrete random variable is one which will address purely a countable form of distinctive values including 0,a million,2,3,4,........ Discrete random variables are many times (yet not inevitably) counts. If a random variable can take purely a finite form of distinctive values, then it must be discrete. Examples of discrete random variables incorporate the form of youngsters in a family, the Friday evening attendance at a cinema, the form of sufferers in a physician's surgical treatment, the form of defective mild bulbs in a container of ten. so definite, you does not say sixty two a million/2 beats according to minute... you're able to say sixty two bpm or sixty two bpm My source is Yale college Stat branch and that i pay attention they are pretty clever up there.


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