因式分解點計呀??好似下面嘅咁:
回答 (2)
2011-09-22 5:18 am
✔ 最佳答案
6(a - 1)b³ + (1 - a)b²= 6(a - 1)b³ + [-(a - 1)]b² ...... 因 (1- a) = -(a - 1)
= 6(a - 1)b³ - (a - 1)]b² ...... 正負得負
= b²(a - 1)(6b - 1) ...... 抽出公因式 b²(a - 1)
參考: 賣女孩的火柴
2011-09-22 5:05 am
b^2(a-1)(6b-1)
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110921000051KK00815