工數複變算式問題
2011-09-21 4:32 am
圖片參考：http://imgcld.yimg.com/8/n/AD07694354/o/161109200601413872618340.jpg
請問這式子怎麼算，熊熊想不起來。
請問這式子怎麼算，熊熊想不起來。
回答 (2)
2011-09-21 10:08 am
2011-09-21 4:43 am
[Cos(π/4)+iSin(π/4)]/(2i)－[Cos(3π/4)+iSin(3π/4)]/(2i)SolA=[Cos(π/4)+iSin(π/4)]/(2i)－[Cos(3π/4)+iSin(3π/4)]/(2i)2Ai=[Cos(π/4)+iSin(π/4)]－[Cos(3π/4)+iSin(3π/4)]=[Cos(π/4)－Cos(3π/4)]+i [Sin(π/4)－Sin(3π/4)]=√2A=√2/(2i)=－i√2/2
收錄日期: 2021-04-30 16:04:19
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110920000016KK06014