For the following 3 x 3 determinant, show that
| 1 x + y x^2 + xy + y^2 |
| 0 1 x + y + z |
| z z^2 z^3 - 1 |
= xyz - 1
Determinant
2011-09-17 8:00 pm
回答 (1)
2011-09-17 8:36 pm
收錄日期: 2021-04-23 23:24:58
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