求 e^ex^x 的導數
2011-09-15 6:26 am
回答 (1)
2011-09-15 6:29 am
✔ 最佳答案
y = e^(xe^x)lny = xe^x
1/y * dy/dx = e^x + xe^x = (1+x)e^x
dy/dx
= e^(xe^x) (1+x)e^x
= (1+x)e^[(1+e^x)x]
參考: Hope the solution can help you^^”
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https://hk.answers.yahoo.com/question/index?qid=20110914000051KK00958