實數及復數(急!!!!!)
簡化下列各式:
(3+√2)(√2)
=
(√3)(2-√18)
回答 (4)
✔ 最佳答案
呢條數用兩招
a(b + c) = ab + ac
同√a * √b = √(ab)
(3 + √2)(√2)
= 3√2 + √2 * √2
= 3√2 + 2
(√3)(2 - √18)
= 2√3 - √54
= 2√3 - √9*√6
= 2√3 - 3√6
您好,我是 lop,高興能解答您的問題。
(1)
(3+√2)(√2)
= 3√2 + √2×√2
= 2 + 3√2
(2)
(√3)(2-√18)
= 2√3 - √2 × √18
= 2√2 - √2 × √2 × √9
= 2√2 - 2 × 3
= 2√2 - 6
2011-09-20 17:56:24 補充:
correction 003 :
(1)
(3+√2)(√2)
= 3√2 + √2×√2
= 2 + 3√2
(2)
(√3)(2-√18)
= 2√3 - √2 × √18
= 2√2 - √3 × √2 × √9
= 2√2 - 3 × √6
= 2√2 - 3√6
參考: Hope I Can Help You ^_^ ( From me )
(3+square root2)(square root2)
=3square root2+(square root2)^2
=3square root2+2
(square root 3)(2-square root18)
=2square root3-square root(3*18)
=2square root3-square root54
=2square root3-3square root6
參考: me
收錄日期: 2021-04-13 18:14:03
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110913000051KK00836
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