number system

2011-09-13 2:18 am
It is given that m+1/m=2
圖片參考:http://upload.wikimedia.org/math/0/0/e/00e61be02b9ecec6a3fd923288029dbd.png
3 . Find the value of each of the following.
(a)m^2+1/m^2
(b)m-1/m
(c)m^2-1/m^2

回答 (2)

2011-09-13 2:26 am
✔ 最佳答案
It is given that m+1/m=2√3 . Find the value of each of the following.
(a)m^2+1/m^2
m+1/m=2√3
(m+1/m)^2 =(2√3)^2
m^2 + 1/m^2 + 2 = 12
m^2 + 1/m^2 = 10
(b)m-1/m
m^2 + 1/m^2 = 10
m^2 + 1/m^2 - 2 = 8
(m - 1/m)^2 = 8
m - 1/m = 2√2
(c)m^2-1/m^2
(m - 1/m)(m + 1/m) = m^2 - 1/m^2
(2√2)(2√3) = m^2 - 1/m^2
m^2 - 1/m^2 = 4√6
參考: Hope the solution can help you^^”
2011-09-13 2:53 am

http://s1099.photobucket.com/albums/g395/jasoncube/?action=view¤t=mathgraph-4.jpg
圖片參考:http://imgcld.yimg.com/8/n/HA00016323/o/701109120047813873456890.jpg


2011-09-12 18:56:11 補充:
*CORRECTION:

(a), 2nd line should be:

(m+1/m)²=(2√3)²
參考: Hope I can help you! ^_^ (From me)


收錄日期: 2021-04-13 18:14:09
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110912000051KK00478

檢視 Wayback Machine 備份