數學的疑難-解方程組兩題

2011-09-11 11:23 pm
1.
x + y = axy -------(1)
y + z = byz -------(2)
z + x = czx -------(3)

2.
x ( y + z - x ) = 30 - 2x² -------(1)
y ( x - y + z ) = 52 - 2y² -------(2)
z ( x + y - z ) = 78 - 2z² -------(3)

回答 (1)

2011-09-12 12:15 am
✔ 最佳答案
1)x + y = axy -------(1)
y + z = byz -------(2)
z + x = czx -------(3)當 x , y , z ≠ 0 :1/y + 1/x = a .....(1)
1/z + 1/y = b .....(2)
1/x + 1/z = c .....(3)((1) + (2) + (3)) / 2 :1/x + 1/y + 1/z = (a + b + c)/2 .....(4)(4) - (1) :1/z = (a + b + c)/2 - a
z = 2 / (b + c - a)(4) - (2) :1/x = (a + b + c)/2 - b
x = 2 / (a + c - b)(4) - (3) :1/y = (a + b + c)/2 - c
y = 2 / (a + b - c)當 x , y , z 其一為0 , x = y = z = 0
2)x ( y + z - x ) = 30 - 2x² -------(1)
y ( x - y + z ) = 52 - 2y² -------(2)
z ( x + y - z ) = 78 - 2z² -------(3)==>x (x + y + z) = 30 .....(1)
y (x + y + z) = 52 .....(2)
z (x + y + z) = 78 .....(3)(1) + (2) + (3) :(x + y + z)² = 160
x + y + z = √160 或 - √160 , 代回 (1) , (2) , (3) :x = ± 30 / √160 y = ± 52 / √160 z = ± 78 / √160


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