find dy/dx
1/x^2+1/y^2-1/xy=0
differentiation
2011-09-11 7:55 pm
回答 (2)
2011-09-11 9:11 pm
✔ 最佳答案
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2011-09-11 15:42:12 補充：
HERE:
http://s1099.photobucket.com/albums/g395/jasoncube/?action=view¤t=19d59741.jpg
參考: Hope I can help you! ^_^ (From me), Hope I can help you! ^_^ (From me)
2011-09-12 6:17 am
1/x^2 + 1/y^2 - 1/xy = 0
y^2 +x^2 -xy = 0
y= (1 +/- i√3)x/2
dy/dx = (1 +/- i√3) / 2
y^2 +x^2 -xy = 0
y= (1 +/- i√3)x/2
dy/dx = (1 +/- i√3) / 2
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