The markings on a calibrated thermometer have faded away. We know that the column lengths for 0℃ and 80℃ are 6 cm and 21 cm respectively. What is the column length for 37℃ ?
我想問下點計? 要有過程...希望吾好太複雜...Thank you!
F.3 Phy問題...Plz Help!
2011-09-11 8:21 am
回答 (3)
2011-09-11 8:39 am
✔ 最佳答案
你要明白column length點解先，column length係水銀柱高度，係零度同八十度有兩個高度，呢兩個數值應該係參考某一點而得出，可能係溫度計最低點，不過邊度都唔緊要，佢地嘅差有15cm，而15cm相當於80度溫差，咁除一除得到一度C係0.1875cm，而家問37度C時column length有幾長，咁你將37x0.1875就得到6.3975cm，但唔係答案，因37度C係高過0度C，而0度C有6cm長，所以你要加上6cm=12.9375。
2011-09-11 9:00 am
雖然我讀中文中學 旦我大概估到問咩 溫度計0c 6 cm 80c 21cm 溫度相距80-0 =80 刻度相距21-6 =15 每一度的刻度 =15/80=0.1875cm. 所以37c = 37x0.1875+6 =12.9375 cm Ps:要加返6 是因為0度是由6cm開始的。 希望幫到你
參考: Me
2011-09-11 8:44 am
There is an increase of (21-6) cm = 15 cm of column length for a temperature hange of 80 degrees C. Hence, the calibration should be
= 15/80 cm/C = 0.1875 cm/C
Therefore, at 37'C, the increase in column length = 37 x 0.1875 cm = 6.9375 cm
The column length = (6.9375 + 6) cm = 12.9375 cm
= 15/80 cm/C = 0.1875 cm/C
Therefore, at 37'C, the increase in column length = 37 x 0.1875 cm = 6.9375 cm
The column length = (6.9375 + 6) cm = 12.9375 cm
收錄日期: 2021-04-20 15:17:04
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