急F4 Equations of Straight Line

2011-09-10 11:16 pm
請詳細教我做以下幾條 :
用公式 L1 : y=m1x+c1 及 L2 : y=m2x=c2


圖片參考:http://imgcld.yimg.com/8/n/HA00997022/o/701109100048913873456020.jpg

回答 (1)

2011-09-11 3:59 am
✔ 最佳答案
1a. Since one is along y-axis and one's along x-axis,
therefore, only 1 interception point
b. Since both are along x-axis and c1 =/= c2
therefore, no intersection point

2a. For both are deg 1,
L1 : y = 2x
L2 : y = -2x
Since m1 =/= m2, therefore they have 1 intersection point
b. For both are deg 1,
L1 : y = x/2
L2 : y = x/2 - 1
Since m1 = m2, c1 =/= c2, therefore they have no intersection point

3a. For both are deg 1,
L1 : x = -5
L2 : y = -2x/3 + 1/3
Since m1=/=m2, therefore they have 1 intersection point
b. For both are deg 1,
L1 : y = 7
L2: x = 2y + 2/3
Since m1 =/= m2, therefore they have 1 intersection point

4. For both are deg 1,
L1 : y = 3x
L2 : y = 3x + 5/2
Since m1 = m2, and c1=/=c2, therefore they have no intersection point

5. For both are deg 1,
L1 : y = x/2 + 2
L2 : y = x/2 + 2
Since L1 = L2, therefore they have infinite intersection point
參考: Hope the solution can help you^^”


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