Two cards drawn randomly from deck of 52 playing cards with replacement.Let
D be random variable representing number of diamonds drawn,represent probability distribution of D by table
M1f6數學題一問?10點
2011-09-08 6:27 am
回答 (2)
2011-09-08 3:36 pm
✔ 最佳答案
D =No. of diamonds drawn with 2 cards.Possible value of D, d = 0, 1, 2.
P(D = 0) = (3/4)(3/4) = 9/16
P(D = 1) = (1/4)(3/4) + (3/4)(1/4) = 6/16
P(D = 2) = (1/4)(1/4) = 1/16.
Note : P(D = 0) + P(D = 1) + P(D = 2) = 1.
2011-09-08 12:01 pm
Assume the question is asking for "the number of diamond cards drawn".
P(drawing 0 diamond cards) = (39/52) * (39/52) = 9/16
P(drawing 1 diamond card ) = (2C1) * (13/52) * (39/52) = 6/16 = 3/8
P(drawing 2 diamond cards) = (13/52) * (13/52) = 1/16
d | 0 | 1 | 2
------------------------------------------------------
P(D=d) | 9/16 | 3/8 | 1/16
P(drawing 0 diamond cards) = (39/52) * (39/52) = 9/16
P(drawing 1 diamond card ) = (2C1) * (13/52) * (39/52) = 6/16 = 3/8
P(drawing 2 diamond cards) = (13/52) * (13/52) = 1/16
d | 0 | 1 | 2
------------------------------------------------------
P(D=d) | 9/16 | 3/8 | 1/16
收錄日期: 2021-04-25 22:39:50
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110907000051KK00999