Given the equation of curve C is y = x^3 + ax + b, where a and b are constants.
And, point P(-0.5,4) is a point on C and the slope of tangent to curve C at P is 2.
Find a and b.
Slope of tangent
2011-09-08 5:04 am
回答 (1)
2011-09-08 5:42 am
✔ 最佳答案
dy/dx = 3x^2 + aSince dy/dx|(x=-0.5) = 2
3(-0.5)^2 + a = 2
a = 5/4
Put a = 5/4, x = -1/2 and y = 4 into the curve C.
4 = (-1/2)^3 + (5/4)(-1/2) + b
b = 19/4
參考: Knowledge is power.
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