數學知識交流---函數

2011-09-07 4:08 am
已知 1^1 + 2^2 + 3^3 + 4^4 + ... + (x-1)^(x-1) + x^x = f(x) , 求 f(x)。

回答 (4)

2011-09-21 6:26 pm
2011-09-12 1:55 am
= summation(x^x)?

Is the general formula required?
2011-09-10 2:23 am
jason ,

yes .

2011-09-10 15:54:26 補充:
我也不記得了 ...
2011-09-10 2:17 am
Do u mean simplify 1^1+2^2+3^3+...+ x^x??

2011-09-10 22:24:24 補充:
it seems that its quite simple...
'1^1+2^2+3^3+...+ x^x'

its difficult to define 'most simple'...


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