數學知識交流---函數
已知 1^1 + 2^2 + 3^3 + 4^4 + ... + (x-1)^(x-1) + x^x = f(x) , 求 f(x)。
回答 (4)
= summation(x^x)?
Is the general formula required?
jason ,
yes .
2011-09-10 15:54:26 補充:
我也不記得了 ...
Do u mean simplify 1^1+2^2+3^3+...+ x^x??
2011-09-10 22:24:24 補充:
it seems that its quite simple...
'1^1+2^2+3^3+...+ x^x'
its difficult to define 'most simple'...
收錄日期: 2021-04-13 18:13:21
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