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中二-三角比 好耐冇計:(
2011-09-07 3:53 am
回答 (2)
2011-09-07 4:18 am
✔ 最佳答案
(a).PQ²=PR²+RQ² (pyth. theorem)
PQ=√(PR²+RQ²)
PQ=√(36²+15²)
PQ=√(1296+225)
PQ=√1521
PQ=39
(b).
sinP×tanP÷cosQ
=(15/39)×(15/36)÷(15/39)
=(15/39)×(15/36)×(39/15)
=15/36
=5/12
參考: Hope I can help you! ^_^ (From me)
2011-09-07 8:15 am
a)PQ^2=36^2+15^2(pyth.theorem)
PQ^2=1521
PQ=39
b)sinP=15/39=5/13
tanP=15/36=5/12
cosQ=15/39=5/13
sinP*tanP/cosQ=(5/13)*(5/12)/(5/13)=5/12
PQ^2=1521
PQ=39
b)sinP=15/39=5/13
tanP=15/36=5/12
cosQ=15/39=5/13
sinP*tanP/cosQ=(5/13)*(5/12)/(5/13)=5/12
參考: me
收錄日期: 2021-04-13 18:14:57
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110906000051KK00777