x^1032093 + x^231234 + x^(x^34328374) = x^1032093 + x^231234 + x^(x^x)
find x .
x^1032093 = x^1032093 + x^2312
2011-08-31 3:47 am
回答 (7)
2011-08-31 7:56 pm
✔ 最佳答案
x^1032093 + x^231234 + x^(x^34328374) = x^1032093 + x^231234 + x^(x^x)
x^(x^34328374) = x^(x^x)
log [x^(x^34328374)] = log [x^(x^x)]
(x^34328374) log x = (x^x) log x
x^34328374 = x^x
log[x^34328374] = log [x^x]
34328374 log x = x log x
x = 34328374
2011-08-31 4:44 am
x^1032093 + x^231234 + x^(x^34328374) = x^1032093 + x^231234 + x^(x^x)
1032093x+231234x+34328374x2 =1032093x+231234x+x3
34328374 =x
x = 34328374
一定岩,,,我計過2次,,仲代埋入條題到!
1032093x+231234x+34328374x2 =1032093x+231234x+x3
34328374 =x
x = 34328374
一定岩,,,我計過2次,,仲代埋入條題到!
參考: me
2011-08-31 4:22 am
how do u know?
2011-08-31 4:20 am
x^1032093 + x^231234 + x^(x^34328374) = x^1032093 + x^231234 + x^(x^x)
x^(x^34328378) = x^(x^x)
x^34328378 = x^x if x=/=1 since ln 1 = 0, => x can be 1,
Therefore, x = 34328378 or 1
2011-08-30 20:43:24 補充：
If x=/= 1, i.e. ln x =/= 0
Therefore, we can use ln in both sides
x^(x^34328378) = x^(x^x)
x^34328378 lnx = x^x lnx
x^34328378 = x^x
34328378 lnx = x lnx
x = 34328378
If x = 1, it's a solution by inputting the x = 1
Hence, x = 34328378 or 1
2011-08-30 21:19:09 補充：
Corrections:
34328378 should be 34328374.... Since i see it wrongly oooooooooooops
x^(x^34328378) = x^(x^x)
x^34328378 = x^x if x=/=1 since ln 1 = 0, => x can be 1,
Therefore, x = 34328378 or 1
2011-08-30 20:43:24 補充：
If x=/= 1, i.e. ln x =/= 0
Therefore, we can use ln in both sides
x^(x^34328378) = x^(x^x)
x^34328378 lnx = x^x lnx
x^34328378 = x^x
34328378 lnx = x lnx
x = 34328378
If x = 1, it's a solution by inputting the x = 1
Hence, x = 34328378 or 1
2011-08-30 21:19:09 補充：
Corrections:
34328378 should be 34328374.... Since i see it wrongly oooooooooooops
2011-08-31 4:11 am
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和批發comingzoo的Google搜尋結果,
明顯是廣告
和批發comingzoo的Google搜尋結果,
明顯是廣告
2011-08-31 3:53 am
x can also be 34328374 !
2011-08-31 10:12:16 補充：
I think this question is easy but seems hat no one answered correctly .
And
x^(x^x) = x^(x^34328374)
x^x = x^34328374 ( maybe not correct ) <--- don't delete the x , or you may lost answer(s) like if you delete one more 'x' , you wil miss a solution 1 .
2011-08-31 10:14:08 補充：
Note that x can be -1 .
2011-08-31 10:12:16 補充：
I think this question is easy but seems hat no one answered correctly .
And
x^(x^x) = x^(x^34328374)
x^x = x^34328374 ( maybe not correct ) <--- don't delete the x , or you may lost answer(s) like if you delete one more 'x' , you wil miss a solution 1 .
2011-08-31 10:14:08 補充：
Note that x can be -1 .
2011-08-31 3:49 am
x=1..............
收錄日期: 2021-04-13 18:12:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110830000051KK01207