Mathematics

2011-08-31 2:38 am
Insert 2 numbers between 5 and 17 so that the sequence formed is an arithmetic sequence.

Find the number of terms of the geometic sequence 2,6,18...,4374.

Find the number of terms of the geometic sequence 3.2,-1.6,0.8,...,-0.00625

Find the general term of the geometic sequence T(2)=1/9,T(5)=3

Find the general term of the geometic sequence T(2)=6,T(7)=192

回答 (1)

2011-09-04 2:17 am
✔ 最佳答案
5=1*4+1
17=4*4+1
the 2 numbers=2*4+1 and 3*4+1=9 and 13
2=2*3^0
6=2*3^1
18=2*3^2
4374=2*3^7
number of terms=7-0+1=8
3.2=512/160=-(-2)^9/160
-1.6=-256/160=-(-2)^8/160
0.8=128/160=-(-2)^7/160
-0.00625=-1/160=-(-2)^0/160
number of terms=9-0+1=10
1/9=3^(2-4)
T(2)=3^(2-4)
3=3^(5-4)
T(5)=3^(5-4)
gernal term T(n)=3^(n-4)
6=6*2^(2-2)
T(2)=6*2^(2-2)
192=6*2^(7-2)
T(7)=6*2^(7-2)
general term T(n)=6*2^(n-2)
參考: me


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