這題目點做xd?

Mr. Chu owns two ducks farm Aand B. The number of ducks in farmA is 36% of that in farm B. It is known that 48% of theducks in farm A are female while 35% of ducks in farm B are male. What is the percentage ofthe total number of female ducks in the two farms?


Let n be the number of ducks in farm B.
Then, number of ducks in farm A = n * 36% = 0.36n
Total number of ducks in the two farms = n + 0.36n = 1.36n

Number of female ducks in farm A = 0.36n * 48% = 0.1728n
Number of female ducks in farm B = n * (1 - 35%) = 0.65n
Total number of female ducks in the two farms = 0.1728n + 0.65n = 0.8228n

Percentage of the total number of female ducks in the two farms
= (0.8228/1.36) * 100%
= 60.5%