切線TANGENT問題
2011-08-29 6:42 am
回答 (1)
2011-08-29 7:20 am
✔ 最佳答案
Let Oc' 丄 BC , △ COc' ~ △CABSoCc' / Oc' = CB / AB(12 - r) / r = 12 / 4r = 3Area of the shaded region = △ABC - semi-circle= 12 * 4 / 2 - π * 3² / 2= 24 - 9π/2= 3(16 - 3π)/2
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