let f(x)=-x^2+10x+5.p and q are two unequal real numbers such that f(p)=f(q).
Find value of (p+q)/2
中五數學題一問
2011-08-29 1:39 am
回答 (2)
2011-08-29 1:51 am
✔ 最佳答案
Hi ! I am lop****** , feel happy to answer your question.Q :let f(x)=-x^2+10x+5.p and q are two unequal real numbers such that f(p)=f(q).
Find value of (p+q)/2
A :
-p^2+10p+5 = -q^2+10q+5
10p-p^2 = 10q-q^2
p(10-p) = q(10-q)
If p ≠ q , that means p or q = 0 or 10
then (p+q)/2 = 10/2 = 5
參考: Hope I Can Help You ^_^ ( From me )
2011-08-29 2:21 am
let f(x)=-x^2+10x+5.p and q are two unequal real numbers such that f(p)=f(q).
Find value of (p+q)/2
(p+q)/2 = 5
Find value of (p+q)/2
(p+q)/2 = 5
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