Tom and Mary are due south and due east of bus stop respectively,distance
between them is 60m.They walk toward bus stop at same time with their own
constant speeds.After 6 seconds,they both 27m away from bus stop.If Mary walks slower than tom by2m/s,find their speeds.
f5數學題一問?10點
2011-08-28 6:28 pm
回答 (1)
2011-08-28 6:49 pm
✔ 最佳答案
Initially, Mary, Tom and the bus stop form a right-angled triangle with hypotenuse (斜邊) 60m. Let v be the speed of Tom and the speed of Mary is therefore (v-2)
By distance travelled = speed x time
Distance travelled by Tom in 6 sec = 6v m
Distance travelled BY Mary in 6 sec = 6(v-2) m
As their final distances from the bus stop are both 27 m
By Pythagoras' Theorem, (27+6v)^2 + (27+ 6(v-2)^2 = 60^2
By solving the quadratic equation, you will get the answer! ^^
參考: my maths knowledge
收錄日期: 2021-04-23 20:46:24
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