Maths question(要完整的算式)

Chun Wing

2011-08-23 2:13 am

圖片參考：http://imgcld.yimg.com/8/n/HA04589620/o/701108220102513873447550.jpg
In the diagram, a mouse at point A runs due east along one side of the rectangle. At the same time, a cat at point A runs due south along another side of the rectangle. Finally, they meet at point C, where BC = 60cm. Given that the speed of the mouse is 11/14 times of that cat, find the perimeter of the rectangle in metre.

回答 (1)

用戶27207

2011-08-23 6:13 am

✔ 最佳答案

Since the speed of the mice is 11/14 of the speed of the cat,
so if they run together in a same period,
the distance run by the mice is 11/14 of distance run by the cat.

In this case, they run in a same period,
the difference of the distance run by the cat and the mice is 60.

The distance run by the cat is AB+BC,
the distance run by the mice is AB-BC.
Their difference=2BC=2*60=120

Let x be the distance run by the cat,
the distance run by the mice will be (11/14)x,
and their difference is 120.

x-(11/14)*x=120
(14x-11x)/14=120
3x=1680
x=560

So, the distance run by the cat is 280cm,
the distance run by the mice will be (11/14)*560=440.
The total distance run by the cat and the mice,
=perimeter of the rectangle=560+440=1000cm=10m.

參考: Hope I can help you! ^_^ (From me)

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