CHEMCHEM

2011-08-22 4:46 am
點解larger dispersion forces between chlorine molecules outweighs dipole dipole forces between HCL molecule?? ???
更新1:

問題其實係問ACCOUNT FOR THE DIFFERENCE IN BOILING POINTS FOR EACH OF THE FOLLOWING PAIR OF SUBSTANCE: HYDROGEN CHLORIDE(HCL):b.p.:-85 and CHLORINE(HL2):b.p. -34

回答 (2)

2011-08-31 6:26 am
✔ 最佳答案
if we compare the boiling points of molecules with similar molecular size:
Strength: (hydrogen bonds) > (permanent dipole - permanent dipole attractions) > (instantaneous dipole - induced dipole attractions)
Boiling point: (hydrogen bonds) > (permanent dipole - permanent dipole attractions) > (instantaneous dipole - induced dipole attractions)

However, if we compare the boiling points of molecules with largely different relative molecular masses, the one with a larger molecular size will have stronger intermolecular forces.
This is because permanent dipole - permanent dipole attractions and instantaneous dipole - induced dipole attractions are affected by molecular size.
Dispersion forces tend to be the most important type of intermolecular forces for these molecules
i.e. dispersion force > dipole-dipole attraction

therefore, in this case, as HCl and Cl2 are of largely different relative molecular masses, one is 36.5 and another is 71.0,
therefore, dispersion forces tend to be the most important type of intermolecular forces to be considered
therefore, the boiling point of Cl2 is higher than that of HCl
2011-08-22 8:27 pm
Question is incomplete.
Please supplement.


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