y = x^2+2x-3
First I thought the answer should be (-oo,-3]u[1,oo) cause' (x+3)(x-1)>=0
But the answer appear to be (-oo,oo)
I don't understand, can someone explain?thanks
How to find domain of a equation?
2011-08-20 4:29 pm
回答 (2)
2011-08-20 4:41 pm
✔ 最佳答案
hello, firstly you need to understand the concept of domain to solve further problems.ok.dont worry ,let me try to understand you.
domain of function f(x) is defined as those values of x for which function is defined.
as your question is
x^2+2x-3=y,
so,as by defination it is defined for all the values of x.
you can put any value of x in the equation but the function will remain defined.
so its domain is (-infinity,infinity).
i hope you will understand and good luck!!!!
2011-08-20 4:33 pm
Domain means what values can x assume in this expression.
The answer is : (-oo,oo) ; all real numbers.
The answer is : (-oo,oo) ; all real numbers.
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