3條f.2升f.3數學(指數)
2011-08-19 8:22 am
回答 (4)
2011-08-19 11:17 pm
✔ 最佳答案
1.0的位值=2^22.1^2*2^3+1^3*2+1^4*2^4
=1*2^3+1*2+1*2^4
=1*2^4+1*2^3+1*2
=1*2^4+1*2^3+0*2^2+1*2^1+0*2^0
=11010(2)
3.110/2=55...0
55/2=27...1
27/2=13...1
13/2=6...1
6/2=3...0
3/2=1...1
1/2=0...1
so 110(10)=1101110(2)
參考: just my answer
2011-08-19 8:17 pm
(1). 2^2
(2). 那些1既x次方應該沒影響，所以照平常:
1*2^4+1*2^3+1*2^1
=11010
(3).想快D就用計數機- -
我老師就係咁教:
110/2=55...0
55/2=27...1
27/2=13...1
13/2=6...1
6/2=3...0
3/2=1...1
1/2=0...1
把餘數由下至上咁寫就搵到110既二進數係1101110
(2). 那些1既x次方應該沒影響，所以照平常:
1*2^4+1*2^3+1*2^1
=11010
(3).想快D就用計數機- -
我老師就係咁教:
110/2=55...0
55/2=27...1
27/2=13...1
13/2=6...1
6/2=3...0
3/2=1...1
1/2=0...1
把餘數由下至上咁寫就搵到110既二進數係1101110
2011-08-19 6:56 pm
2011-08-19 8:38 am
1. 右邊數過去,2^0,2^1,2^2
所以係2^2
2. 1^2x2^3+1^3x2+1^4x2^4
=2^3x2^1x2^4
=11010
3. 1101110
所以係2^2
2. 1^2x2^3+1^3x2+1^4x2^4
=2^3x2^1x2^4
=11010
3. 1101110
收錄日期: 2021-04-13 18:10:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20110819000051KK00038