✔ 最佳答案
1. (2/3)^0 *(4/3)^(-2)
=1* 1/[(4/3)^2)]
=1/(16/9)
=9/16
2. (2^x)^(-6) *(8^x)
=[2^(-2*3*x)] *[(2^3)^x]
=[(2^3)^x]/[(2^3)^(2x)]
=1/[(2^3)^x]
=1/(8^x)
=2^(-3x)
So, the answer is A.
3. [a^(2x) *b^(2y)]/[a^(-2y) *b^(2x)]
=(a^x *b^y *a^y *b^x)^2
=[a^(x+y) *b^(x+y)]^2
=(ab)^[2(x+y)]
=(ab)^(2x+2y)
4. x=√2
x^2=2
x^(-2)=1/2
24x^(-2)=24(1/2)
=12
參考: Hope I can help you! ^_^ (From me)