F.2數學(20點

2011-08-17 6:32 am
俾埋計算過程.thx
1.It us known that the H.C.F of a given number and 63 is 9. Find two possible valuse of the given number.

2.It is know that the L.C.M of a given number and 48 is 144. Find two possible valuse of the given number.

3.(-3/21)÷(-39/42)

4.It is know that the product of 4.5 and y is not less than 9.
a) Formulate an inequality to represent the above relation.
b) Write down three integers that satisfy the inequality in question (a)

5.In each of the following, a^n is the general term of the sequence. Find the 1st term and the 5th term of the sequence.
a) a^n = 6n-1
b) a^n - 1/2n

萬分感謝QVQ
更新1:

Andy has x books.The number of books that Cindy has is 2 times that of Andy while the number of books that Ken has is 5 less than Cindy a)How many books does Cindy have? b)How many books does Ken have? c)How many books do Cindy and Ken have altogether? d)How many less books does Andy have then Ken?

回答 (2)

2011-08-17 7:45 pm
✔ 最佳答案
Hi ! I am lop****** , feel happy to answer your question.

Q 1 : It us known that the H.C.F of a given number and 63 is 9. Find two possible valuse of the given number.

A 1 : 9 or 18

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Q 2 : It is know that the L.C.M of a given number and 48 is 144. Find two possible valuse of the given number.

A 2 : 72 or 144

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Q 3 : (-3/21)÷(-39/42)

A 3 :

(-3/21) ÷ (-39/42)
= (-1/7) × (42/-39)
= -6/-39
= 6/39

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Q 4 : It is know that the product of 4.5 and y is not less than 9.

A 4 :

a) Formulate an inequality to represent the above relation.

4.5y > 9

b) Write down three integers that satisfy the inequality in question (a)

3 , 4 or 5

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Q 5 : In each of the following, a(n) is the general term of the sequence. Find the 1st term and the 5th term of the sequence.

A 5 :

a) a(n) = 6n-1

The first term : 6×1-1 = 5
The 5th term : 6×5-1 = 29

b) a(n) = 1/2n

The first term : 1/(2×1) = 1/2
The 5th term : 1/(2×5) = 1/10

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Q 6 : Andy has x books.The number of books that Cindy has is 2 times that of Andy while the number of books that Ken has is 5 less than Cindy

A 6 :

a)How many books does Cindy have?

Cindy has : 2x books .

b)How many books does Ken have?

Ken has : ( 2x - 5 ) books .

c)How many books do Cindy and Ken have altogether?

Cindy and Ken have : 2x + ( 2x - 5 ) = ( 4x - 5 ) books .

d)How many less books does Andy have then Ken?

The books Andy has less than Ken : 2x - 5 - x = ( x - 5 ) books .

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參考: Hope I Can Help You ^_^ ( From me )
2011-08-17 10:13 am
Please check the wording of question 5 (a)
a) a^n = 6n-1

2011-08-18 11:19:01 補充:
Question 3.
The fraction can be further reduced to 2/13


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