Simplify
6^(2x)/(4^x)(3^2)
(1-cosθ)(1+cosθ)/tan^2θ
maths.
2011-08-13 6:35 am
回答 (1)
2011-08-13 7:03 am
✔ 最佳答案
Simplify6^(2x)/[(4^x)(3^2)]
=[2^(2x)]*[3^(2x)]/[(2^2x)*9]
=3^(2x)/9
=3^(2x－2)
(1－Cosθ)(1+Cosθ)/Tan^2θ
=(1－Cos^2 θ)/Tan^2θ
=Sin^2 θ/(Sin^2 w/Cos^2 θ)
=Cos^2θ
收錄日期: 2021-04-30 15:59:48
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https://hk.answers.yahoo.com/question/index?qid=20110812000051KK01317