ax-ay+7xy^2-7x^2y
求好心人列出詳細步驟!
恆等式與因式分解的一條數學題
2011-08-12 12:22 am
回答 (4)
2011-08-12 12:30 am
✔ 最佳答案
ax-ay+7xy^2-7x^2y=a(x-y)+7xy(y-x)
=a(x-y)+7xy[-(x-y)]
=a(x-y)-7xy(x-y)
=(a-7xy)(x-y)
參考: me
2011-08-13 10:07 pm
ax-ay+7xy^2-7x^2y
=a(x-y)+7xy(y-x)
=a(x-y)-7xy(x-y)
=(x-y)(a-7xy)
=a(x-y)+7xy(y-x)
=a(x-y)-7xy(x-y)
=(x-y)(a-7xy)
2011-08-12 6:04 pm
ax-ay+7xy^2-7x^2y
=a(x-y)+7xy(y-x)
=a(x-y)-7xy(x-y)
=(a-7xy)(x-y)
=a(x-y)+7xy(y-x)
=a(x-y)-7xy(x-y)
=(a-7xy)(x-y)
參考: just my answer
2011-08-12 12:32 am
ax-ay+7xy^2-7x^2y
= (ax-ay) + (7xy^2-7x^2y)
= a(x - y) + 7xy(y - x)
= a(x - y) + (7xy)(-1)(x - y)
= a(x - y) - (7xy)(x - y)
= (a - 7xy)(x - y)
= (ax-ay) + (7xy^2-7x^2y)
= a(x - y) + 7xy(y - x)
= a(x - y) + (7xy)(-1)(x - y)
= a(x - y) - (7xy)(x - y)
= (a - 7xy)(x - y)
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