恆等式與因式分解的一條數學題

2011-08-12 12:22 am

ax-ay+7xy^2-7x^2y

求好心人列出詳細步驟!

回答 (4)

2011-08-12 12:30 am

✔ 最佳答案

ax-ay+7xy^2-7x^2y

=a(x-y)+7xy(y-x)
=a(x-y)+7xy[-(x-y)]
=a(x-y)-7xy(x-y)
=(a-7xy)(x-y)

參考: me

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2011-08-13 10:07 pm

ax-ay+7xy^2-7x^2y

=a(x-y)+7xy(y-x)

=a(x-y)-7xy(x-y)

=(x-y)(a-7xy)

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2011-08-12 6:04 pm

ax-ay+7xy^2-7x^2y
=a(x-y)+7xy(y-x)
=a(x-y)-7xy(x-y)
=(a-7xy)(x-y)

參考: just my answer

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2011-08-12 12:32 am

ax-ay+7xy^2-7x^2y
= (ax-ay) + (7xy^2-7x^2y)
= a(x - y) + 7xy(y - x)
= a(x - y) + (7xy)(-1)(x - y)
= a(x - y) - (7xy)(x - y)
= (a - 7xy)(x - y)

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